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4p^2+5p-125=0
a = 4; b = 5; c = -125;
Δ = b2-4ac
Δ = 52-4·4·(-125)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-45}{2*4}=\frac{-50}{8} =-6+1/4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+45}{2*4}=\frac{40}{8} =5 $
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